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Home » You Won’t Believe Which Male Disney Characters Shocked Fans Forever! - jntua results

You Won’t Believe Which Male Disney Characters Shocked Fans Forever! - jntua results

📅 March 10, 2026 👤 scraface

Mar 10, 2026

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📌 2\sin x + 3\cos x = \sqrt{13} \sin(x + \phi)

📌 The range of $ \sqrt{13} \sin(x + \phi) $ is $ [-\sqrt{13}, \sqrt{13}] $.

📌 2\sin x + 3\cos x + 4 \in [4 - \sqrt{13}, 4 + \sqrt{13}]

📌 Since $ \sqrt{13} \approx 3.605 $, $ 4 - \sqrt{13} \approx 0.395 > 0 $, so the expression never reaches zero.

📌 Therefore, the absolute value $ |2\sin x + 3\cos x + 4| $ achieves its minimum at the minimum of the continuous function on an interval where it is always positive.

📌 The minimum occurs when $ 2\sin x + 3\cos x $ is minimized, but since it's always greater than $ -\sqrt{13} $, and greater than $ -4 $, the expression inside is always positive.

📌 \min |2\sin x + 3\cos x + 4| = \min (2\sin x + 3\cos x + 4) = 4 - \sqrt{13} + 0? \quad \text{Wait — no: the minimum of the inner expression is $ 4 - \sqrt{13} \approx 0.395 $, so the minimum of the absolute value is just its minimum value because it's positive.

📌 \min |2\sin x + 3\cos x + 4| = 4 - \sqrt{13} \quad \text{if } 4 - \sqrt{13} > 0

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