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Solving for \( r \), \( r = \frac{C}{2\pi} = \frac{31.4}{2 \times 3.14159} \approx \frac{31.4}{6.28318} \approx 5 \).

Solving for \( r \), \( r = \frac{C}{2\pi} = \frac{31.4}{2 \times 3.14159} \approx \frac{31.4}{6.28318} \approx 5 \).

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March 9, 2026
A box contains 3 red, 4 blue, and 5 green marbles. If one marble is drawn at random, what is the probability it is not blue?

A box contains 3 red, 4 blue, and 5 green marbles. If one marble is drawn at random, what is the probability it is not blue?

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March 9, 2026
Total marbles = \( 3 + 4 + 5 = 12 \).

Total marbles = \( 3 + 4 + 5 = 12 \).

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March 9, 2026
Non-blue marbles = \( 3 + 5 = 8 \).

Non-blue marbles = \( 3 + 5 = 8 \).

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March 9, 2026
Probability = \( \frac{8}{12} = \frac{2}{3} \).

Probability = \( \frac{8}{12} = \frac{2}{3} \).

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March 9, 2026
If the function \( f(x) = 3x^2 - 2x + 1 \), find \( f(2) \).

If the function \( f(x) = 3x^2 - 2x + 1 \), find \( f(2) \).

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March 9, 2026
Substitute \( x = 2 \): \( f(2) = 3(2)^2 - 2(2) + 1 = 12 - 4 + 1 = 9 \).

Substitute \( x = 2 \): \( f(2) = 3(2)^2 - 2(2) + 1 = 12 - 4 + 1 = 9 \).

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March 9, 2026
Use the Pythagorean theorem: \( \text{base}^2 + 8^2 = 10^2 \).

Use the Pythagorean theorem: \( \text{base}^2 + 8^2 = 10^2 \).

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March 9, 2026
\( \text{base}^2 = 100 - 64 = 36 \).

\( \text{base}^2 = 100 - 64 = 36 \).

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March 9, 2026
Base = \( \sqrt{36} = 6 \) meters.

Base = \( \sqrt{36} = 6 \) meters.

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March 9, 2026

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  • Non-primes: each has 3 choices → $ 3 \times 3 = 9 $, but we...
  • For Case 1:
  • Odd primes: 0 → contribution: 0 odd values
  • Odd non-primes: 0 → 0
  • Even non-primes: 0 → 0
  • So total odd count = 0 → even → valid
  • Choose 2 positions for primes: $ \binom{4}{2} = 6 $
  • Assign (2,2) to them: 1 way
  • Assign (4 or 6, 4 or 6, 4 or 6, 4 or 6) to non-primes: $ 3 \...
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  • So for Case 1:
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