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Home » You Won’t Believe How Rare These Breeding Bengal Cats Actually Are! - jntua results

You Won’t Believe How Rare These Breeding Bengal Cats Actually Are! - jntua results

📅 March 10, 2026 👤 scraface

Mar 10, 2026

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📌 Substitute \(

📌 ho = c \sin(\phi)\) into the expressions:

📌 x = c \sin(\phi) \cdot \sin(\phi) \cos heta = c \sin^2(\phi) \cos heta

📌 y = c \sin^2(\phi) \sin heta

📌 z = c \sin(\phi) \cos(\phi)

📌 Now compute \(x^2 + y^2\):

📌 x^2 + y^2 = c^2 \sin^4(\phi) (\cos^2 heta + \sin^2 heta) = c^2 \sin^4(\phi)

📌 From the identity \(\sin^2(\phi) = rac{

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But let's simplify: 500 data points/hour → 10,000 / 500 = 20 hours.
Alternatively, per data point: 0.2 ms = 0.0002 seconds. 10,000 × 0.000...
#### 0.000555
Using direct hours calculation: 10,000 data points × 0.2 ms/data point...
Convert to hours: 2,000 ms = 0.002 seconds = 0.002 / 3600 ≈ 5.555... ×...
But this seems inconsistent. Re-evaluate:
ms per data point = 0.2 × 10⁻³ seconds = 2 × 10⁻⁴ seconds.
Total time: 10,000 × 2 × 10⁻⁴ = 2 seconds.
Convert to hours: 2 / 3600 ≈ 0.000555... hours.
Thus, the correct answer is:

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