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Home » \[x \approx 1.8\] - jntua results

\[x \approx 1.8\] - jntua results

📅 March 9, 2026 👤 scraface

Mar 09, 2026

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\[ \frac{200}{p} \times p = 200 \text{ dollars} \]
\[ \text{卖出金额} = \text{出售数量} \times \text{出售价格} \]
其中出售数量为 \( \frac{200}{p} \)，价格为 \( p \)，总卖出金额为：
但题目问的是最初卖出的是多少美元，即初始股票售价是否为1000美元的25%上...
设初始买入为1000美元，价格 \( p = 1000 / n \)，售出部分发现剩余价值800...
\[ \frac{800}{n_{\text{rem}}} \]
但价格均为 \( p = 1000/n \)，出售数量为 \( x \)，则：
\[ x \times (1.25p) = \text{总售出金额} \]
\[ (n - x) \times p = 800 \]
\[ n - x = \frac{800}{p} = \frac{800n}{1000} = 0.8n \Rightarrow x = 0....

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