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Home » Thus, the minimum value is $ \boxed4 - \sqrt13 $. - jntua results

Thus, the minimum value is $ \boxed4 - \sqrt13 $. - jntua results

📅 March 10, 2026 👤 scraface

Mar 10, 2026

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ä¸å¿ã \((h, k)\) ã§åå¾ã \(r\) ã®åã®æ¹ç¨å¼ã¯æ¬¡ã®ã¨...
ä¸ããããä¸å¿ \((3, -2)\) ã¨åå¾ \(5\) ãä»£å¥ãã¾ã:
ç¹ \((6, 1)\) ãåä¸ã«ãããç¢ºèªãã¾ã:
\(18
eq 25\) ãªã®ã§ãç¹ \((6, 1)\) ã¯åä¸ã«ã¯ããã¾ããã
#### \((x - 3)^2 + (y + 2)^2 = 25\), ç¹ \((6, 1)\) ã¯åä¸ã«ãã...
äºæ¬¡æ¹ç¨å¼ \(2x^2 - 4x - 6 = 0\) ãä¸ãããã¦ãã¾ããäº...
x = rac{-b \pm \sqrt{b^2 - 4ac}}{2a}
\(2x^2 - 4x - 6 = 0\) ã§ã¯ã\(a = 2\)ã\(b = -4\)ã\(c = -6\) ã§...

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