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Home » Then the length is \( 3w \) meters. - jntua results

Then the length is \( 3w \) meters. - jntua results

📅 March 10, 2026 👤 scraface

Mar 10, 2026

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📌 Answer: 10 × 20 × (4/8) = 10 × 20 × 0.5 = <<10*20*0.5=100>>100 bytes

📌 But the instruction says difficult enough for math olympiad — so include decimal precision.

📌 Corrected and simplified:

📌 A historian analyzing ENIAC finds each register could store a 20-digit decimal number, requiring 20 × 4 = 80 bits = 10 bytes of memory. The later STOR-MATAC system uses 16 registers, each storing 2 bytes. How many bytes of memory did ENIAC use per register configuration?

📌 Each ENIAC register holds 20 digits × 4 bits = 80 bits = 10 bytes.

📌 But that’s too simple.

📌 Multiply: total ENIAC memory for 10 registers: 10 × 10 = 100 bytes. But question asks per register or total?

📌 How many total bytes does the ENIAC register memory occupy? — total.

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