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Home » The vertex \( x \)-coordinate is \( x = -racb2a = -rac150-10 = 15 \). - jntua results

The vertex \( x \)-coordinate is \( x = -racb2a = -rac150-10 = 15 \). - jntua results

📅 March 9, 2026 👤 scraface

Mar 09, 2026

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Substitute $ d^2 = \frac{28a^2}{9} \Rightarrow d = a\sqrt{\frac{28}{9}...
\frac{a + \frac{1}{2} \cdot \frac{2a\sqrt{7}}{3}}{a - \frac{3}{2} \cdo...
Multiply numerator and denominator by $ 1 + \sqrt{7} $:
\frac{(3 + \sqrt{7})(1 + \sqrt{7})}{3(1 - 7)} = \frac{3(1) + 3\sqrt{7}...
But since the progression is real and the context suggests positive te...
Let $ r = \frac{a + \frac{d}{2}}{a - \frac{3d}{2}} $. Let $ x = \frac{...
r = \frac{1 + \frac{x}{2}}{1 - \frac{3x}{2}}.
Substitute $ x = \sqrt{\frac{28}{9}} = \frac{2\sqrt{7}}{3} $:
r = \frac{1 + \frac{1}{2} \cdot \frac{2\sqrt{7}}{3}}{1 - \frac{3}{2} \...
As before, this evaluates to $ -\frac{5 + 2\sqrt{7}}{9} $, but this is...

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