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Home » The Dirty Secrets of the C Viper You Never Know! - jntua results

The Dirty Secrets of the C Viper You Never Know! - jntua results

📅 March 10, 2026 👤 scraface

Mar 10, 2026

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📌 - 24 = 144

📌 Thus, the sum of all even divisors of 60 is:

📌 \boxed{144}

📌 What is the remainder when the sum \( 1^3 + 2^3 + 3^3 + \dots + 10^3 \) is divided by 11?

📌 We use the formula for the sum of cubes:

📌 Now compute \( 3025 \mod 11 \).

📌 First, reduce 55 modulo 11:

📌 \div 11 = 5 \quad \Rightarrow \quad 55 \equiv 0 \pmod{11}

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