Maximum height = $ \frac(10\sqrt2)^22 \times 9.8 = \frac20019.6 \approx 10.2 \, \textmeters $

Maximum Height of a Projectile: Calculating the Peak Ã¢ÂÂ A Detailed Explanation

When throwing a ball upward or analyzing any vertical motion projectile, understanding how high it can rise is essential. A classic physics formula helps us calculate the maximum height a projectile reaches under gravity. In this article, we explore how to compute maximum height using the equation:

[
\ ext{Maximum height} = rac{(10\sqrt{2})^2}{2 \ imes 9.8} pprox 10.2 , \ ext{meters}
]

Understanding the Context

LetÃ¢ÂÂs break down how this formula is derived, how it applies to real-world scenarios, and why this value matters for physics students, engineers, and enthusiasts alike.

Understanding Maximum Height in Projectile Motion

Maximum height depends on two key factors:
- The initial vertical velocity ((v_0))
- The acceleration due to gravity ((g = 9.8 , \ ext{m/s}^2) downward)

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Key Insights

When a projectile is launched upward, gravity decelerates it until its vertical velocity reaches zero at peak height, after which it descends under gravitational pull.

The vertical motion equation gives maximum height ((h)) when total vertical velocity becomes zero:

[
v^2 = v_0^2 - 2gh
]

At peak ((v = 0)):
[
0 = v_0^2 - 2gh_{max} \Rightarrow h_{max} = rac{v_0^2}{2g}
]

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Final Thoughts

Using the Given Example: ( h_{max} = rac{(10\sqrt{2})^2}{2 \ imes 9.8} )

This specific form introduces a clever choice: ( v_0 = 10\sqrt{2} , \ ext{m/s} ). Why?

First, compute ( (10\sqrt{2})^2 ):
[
(10\sqrt{2})^2 = 100 \ imes 2 = 200
]

Now plug into the formula:
[
h_{max} = rac{200}{2 \ imes 9.8} = rac{200}{19.6} pprox 10.2 , \ ext{meters}
]

This means a vertical launch with speed ( v_0 = 10\sqrt{2} , \ ext{m/s} ) reaches roughly 10.2 meters height before peaking and falling back.

How to Compute Your Own Maximum Height

HereÃ¢ÂÂs a step-by-step guide:

Start with vertical initial velocity ((v_0)) Ã¢ÂÂ either measured or assumed.
2. Plug into the formula:

[
h_{max} = rac{v_0^2}{2 \ imes g}
]