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Home » \frac1k(k+2) = \fracAk + \fracBk+2 - jntua results

\frac1k(k+2) = \fracAk + \fracBk+2 - jntua results

📅 March 9, 2026 👤 scraface

Mar 09, 2026

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🔥 Popular Posts

We need to find the largest positive multiple of 3 such that \( v^2 <...
Find the largest integer \( v \) such that \( v^2 < 200 \). Taking the...
\sqrt{200} \approx 14.14
So \( v \leq 14 \). Now consider the multiples of 3 less than or equal...
Check \( v = 12 \):
12^2 = 144 < 200
Check \( v = 15 \) (next multiple):
15^2 = 225 > 200 \quad \text{(not valid)}
Since 15 exceeds the limit, the largest valid multiple is 12.
Therefore, the largest possible value of \( v \) is \(\boxed{12}\).

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