\frac12 \left( \dbinom60 + \dbinom61 + \dbinom62 + \dbinom63 \right) = \frac12 (1 + 6 + 15 + 20) = \frac422 = \boxed21

\frac12 \left( \dbinom60 + \dbinom61 + \dbinom62 + \dbinom63 \right) = \frac12 (1 + 6 + 15 + 20) = \frac422 = \boxed21 - jntua results

📅 March 10, 2026 👤 scraface

Mar 10, 2026

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