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Home » En résolvant, \(w = 6\), donc la longueur est \(2 \times 6 = 12\). - jntua results

En résolvant, \(w = 6\), donc la longueur est \(2 \times 6 = 12\). - jntua results

📅 March 10, 2026 👤 scraface

Mar 10, 2026

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At $ x = 4 $: $ I(4) = \frac{1}{16 + 16 + 5} = \frac{1}{37} $
C(4) = \frac{1}{10} + \frac{1}{17} + \frac{1}{26} + \frac{1}{37}
We find a common denominator or compute numerically:
$ \frac{1}{10} = 0.1 $
$ \frac{1}{17} \approx 0.0588235 $
$ \frac{1}{26} \approx 0.0384615 $
$ \frac{1}{37} \approx 0.027027 $
Sum $ \approx 0.1 + 0.0588235 + 0.0384615 + 0.027027 = 0.224312 $
But we need an exact fraction. Compute step-by-step:
First, $ \frac{1}{10} + \frac{1}{17} = \frac{17 + 10}{170} = \frac{27}...

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