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Home » A_\textsquare = 4^2 = 16 - jntua results

A_\textsquare = 4^2 = 16 - jntua results

📅 March 9, 2026 👤 scraface

Mar 09, 2026

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📝 Recent Posts

Then $\cos\theta = 1 \Rightarrow \theta = 0^\circ$. But not minimal po...
Wait—what if the equation is:
\cos(\theta + 60^\circ) + \cos(\theta - 60^\circ) = \sqrt{3} \cdot \co...
But that's identity. So instead, suppose the intended equation is:
\cos(\theta + 60^\circ) + \cos(\theta - 60^\circ) = \sqrt{3}
\Rightarrow \cos\theta = \sqrt{3} \quad \text{(impossible)}
Thus, no solution. But to fix, suppose the equation is:
2\cos\theta = \sqrt{3} \Rightarrow \cos\theta = \frac{\sqrt{3}}{2}
\Rightarrow \theta = 30^\circ \text{ or } 330^\circ
Smallest positive is $30^\circ$. But not matching. Re-express the iden...

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